A) 0.00428 moles
B) 428 moles
C) 0.428 moles
D) 0.0428 moles
Correct Answer: C
Solution :
Molarity(M) \[\text{=}\frac{\frac{\text{weight}\,\text{of}\,\text{solute}}{\text{molecular}\,\text{weight}\,\text{of}\,\text{solute}}}{\text{volume}\,\text{of}\,\text{the}\,\text{solution}}\text{ }\!\!\times\!\!\text{ 1000}\] \[=\frac{2.5\times 1000}{58.5\times 100}=0.428\,\text{mol}\]
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