A) \[\text{ }\!\![\!\!\text{ C}{{\text{o}}^{\text{III}}}{{\text{(N}{{\text{H}}_{\text{3}}}\text{)}}_{\text{5}}}\text{Br }\!\!]\!\!\text{ S}{{\text{O}}_{\text{4}}}\]
B) \[C{{o}^{\text{III}}}{{[EDTA]}^{-1}}\]
C) \[{{\text{ }\!\![\!\!\text{ C}{{\text{r}}^{\text{III}}}{{(SCN)}_{6}}]}^{3-}}\]
D) \[[P{{t}^{\text{III}}}{{(N{{H}_{3}})}_{2}}C{{l}_{2}}]\]
Correct Answer: D
Solution :
\[[P{{t}^{\text{III}}}{{(N{{H}_{3}})}_{2}}C{{l}_{2}}]\]shows geometrical isomerism.
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