A) \[3:1\]
B) \[1:3\]
C) \[1:9\]
D) \[9:1\]
Correct Answer: B
Solution :
\[Intensity\propto \,{{(amplitude)}^{2}}\] \[\therefore \] \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{a_{1}^{2}}{a_{2}^{2}}\] \[\frac{1}{9}=\frac{a_{1}^{2}}{a_{2}^{2}}\] \[\Rightarrow \] \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{1}{3}\]
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