A) \[\frac{k}{2}\]
B) \[\frac{2k}{2}\]
C) \[\frac{3k}{2}\]
D) \[\frac{4k}{2}\]
Correct Answer: C
Solution :
Let the force constant of 2nd piece be k As, \[k\propto \,\,\frac{1}{l}\] \[\therefore \] \[\frac{{{k}_{1}}}{{{k}_{2}}}=\frac{{{l}_{2}}}{{{l}_{1}}}\] or \[\frac{k}{{{k}_{2}}}=\frac{2l/3}{l}\] or \[{{k}_{2}}=\frac{3k}{2}\]
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