A) \[4\,\,F\]
B) \[3\,\,F\]
C) \[2\,\,F\]
D) \[F\]
Correct Answer: C
Solution :
\[Y=\frac{F/A}{\Delta l/l}=\frac{F\times l}{A\times \Delta l}\] (where Y is Young's modulus of elasticity) Since, Y, I and A remain same. \[F\propto \,\,\Delta l\] \[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{\Delta {{l}_{1}}}{\Delta {{l}_{2}}}\] \[\Rightarrow \] \[\frac{F}{{{F}_{2}}}=\frac{2\times {{10}^{-3}}}{4\times {{10}^{-3}}}\] \[{{F}_{2}}=2F\]
You need to login to perform this action.
You will be redirected in
3 sec
