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J & K CET Engineering J and K - CET Engineering Solved Paper-2007

  • question_answer
    The-radius of the earth is R. The height of a point vertically above the earth's surface at which acceleration due to gravity becomes \[1%\] of its value at the surface is

    A)  \[8\,\,R\]          

    B)  \[9\,\,R\]

    C)  \[10\,\,R\]         

    D)  \[20\,\,R\]

    Correct Answer: B

    Solution :

    Acceleration due to gravity at a height h from earth's surface \[g'=\frac{GM}{{{(R+h)}^{2}}}\] Since, \[g'=\frac{1}{100}\] of g \[\frac{g}{100}=\frac{GM}{{{(R+h)}^{2}}}\] \[\frac{{{(R+h)}^{2}}}{100}={{R}^{2}}\] \[\left[ \because \,\,\,g=\frac{GM}{{{R}^{2}}} \right]\] \[R+h=10R\] \[h=9R\]


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