J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    Angle between the line \[\frac{x+1}{1}=\frac{y}{2}=\frac{z-1}{1}\] and a normal to the plane \[x-y+z=0\] is

    A)  \[{{0}^{o}}\]

    B)  \[{{30}^{o}}\]

    C)  \[{{45}^{o}}\]

    D)  \[{{90}^{o}}\]

    Correct Answer: A

    Solution :

    Angle between the line and plane is \[\sin \theta =\frac{aa'+bb'+cc'}{\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}\sqrt{a{{'}^{2}}+b{{'}^{2}}+c{{'}^{2}}}}\] \[=\frac{1\times 1+2\times -1+1\times 1}{\sqrt{1+4+1}\sqrt{1+1+1}}\] \[=\frac{1-2+1}{\sqrt{6}\,\sqrt{3}}=0=\sin \,{{0}^{o}}\] \[\Rightarrow \] \[\theta ={{0}^{o}}\]


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