J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    \[\left| \begin{matrix}    1 & 2 & 3  \\    {{1}^{3}} & {{2}^{3}} & {{3}^{3}}  \\    {{1}^{5}} & {{2}^{5}} & {{3}^{5}}  \\ \end{matrix} \right|\] equal to         

    A)  \[1!\,\,2\,\,1\,\,\,3\]

    B)  \[1\,\,!\,\,\,3\,\,!\,\,\,5\,\,!\]

    C)  \[6\,\,!\]

    D)  \[9\,\,!\]     

    Correct Answer: C

    Solution :

    Let \[A=\left| \begin{matrix}    1 & 2 & 3  \\    {{1}^{3}} & {{2}^{3}} & {{3}^{3}}  \\    {{1}^{5}} & {{2}^{5}} & {{3}^{5}}  \\ \end{matrix} \right|\] \[=1.2.3\left| \begin{matrix}    1 & 1 & 1  \\    {{1}^{2}} & {{2}^{2}} & {{3}^{2}}  \\    {{1}^{4}} & {{2}^{4}} & {{3}^{4}}  \\ \end{matrix} \right|\] \[=6\left| \begin{matrix}    1 & 1 & 1  \\    1 & 4 & 9  \\    1 & 16 & 81  \\ \end{matrix} \right|\] \[=6\left| \begin{matrix}    1 & 0 & 0  \\    1 & 3 & 5  \\    1 & 15 & 65  \\ \end{matrix} \right|({{C}_{2}}\to {{C}_{2}}-{{C}_{1}},{{C}_{3}}\to {{C}_{3}}-{{C}_{2}})\] \[=6.3.5\left| \begin{matrix}    1 & 0 & 0  \\    1 & 1 & 1  \\    1 & 5 & 13  \\ \end{matrix} \right|\] \[=90[1(13-5)]\] \[=90\times 8\] \[=720=6!\]


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