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J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    A number n is chosen at random from the set \[\{11,12,13,.....30\}.\]The probability that n is neither divisible by 3 nor divisible by 5 is   

    A)  \[7/20\]           

    B)  \[9/20\]              

    C)  \[11/20\]           

    D)  \[13/20\]           

    Correct Answer: C

    Solution :

    Number which are divisible by either 3 or 5 are 12, 15, 18, 20, 21, 24, 25, 27, 30. Total number = 9 P (number neither divisible by 3 nor 5) \[=1-P\](either divisible by 3 or 5) \[=1-\frac{9}{20}=\frac{11}{20}\]


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