A) \[KOH,alcohol/\Delta \]
B) \[KOH,\text{ }water/\Delta \]
C) \[~Zn,\text{ }alcohol/\Delta \]
D) \[~Na,\text{ }alcohol/\Delta \]
Correct Answer: C
Solution :
1, 2-dihalogen (vicinal) derivatives of the alkanes on reaction with zinc dust and methanol produces alkenes by loss of to halogen atoms (dehalogenation). \[\underset{1,2-\text{dibromopropane}}{\mathop{C{{H}_{3}}-\underset{Br}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-\underset{Br}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}}}\,+Zn\xrightarrow{\text{alcohol/ }\!\!\Delta\!\!\text{ }}\] \[\underset{\text{propylene}}{\mathop{C{{H}_{3}}CH=C{{H}_{2}}}}\,\]
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