A) \[Cu(s)+ZnS{{O}_{4}}(aq)\to CuS{{O}_{4}}(aq)+Zn(s)\]
B) \[Zn(s)+CuS{{O}_{4}}(aq)\to Cu(s)+ZnS{{O}_{4}}(aq)\]
C) \[Ni(s)+ZnS{{O}_{4}}(aq)\to NiS{{O}_{4}}(aq)+Zn(s)\]
D) \[2Na(s)+CdS{{O}_{4}}(aq)\to N{{a}_{2}}S{{O}_{4}}(aq)\]\[+\,Cd(s)\]
Correct Answer: D
Solution :
In Galvanic cell (Daniel cell) the electrical energy is produced from chemical reactions. \[\begin{align} & \text{At}\,\text{anode:}\,\,\,\,\,\,\,\,\,\,\,\,Zn\to Z{{n}^{2+}}+2{{e}^{-}}\,\,\,(oxidation) \\ & \text{At}\,\text{cathode:}\,\,\,\,\,\,\,\underline{C{{u}^{2+}}+2{{e}^{-}}\to Cu\,\,\,(reduction)} \\ & \text{Cell}\,\text{reaction:}\,\,\,Zn\,+C{{u}^{2+}}\to Z{{n}^{2+}}+Cu \\ \end{align}\] or \[Zn(s)+CuS{{O}_{4}}(aq)\to Cu(s)+ZnS{{O}_{4}}(aq)\]
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