J & K CET Engineering J and K - CET Engineering Solved Paper-2006

  • question_answer
    A bar magnet is held at right angles to a uniform magnetic field. The couple acting on the magnet is to be halved by rotating it from this position. The angle of rotation is

    A)  \[{{60}^{o}}\]          

    B)  \[{{45}^{o}}\]

    C)  \[{{30}^{o}}\]          

    D)  \[{{75}^{o}}\]

    Correct Answer: A

    Solution :

    \[\tau =MB\,\,\sin \,\theta \] where       \[\theta ={{90}^{o}}\] \[\therefore \] \[\tau =MB\] Given,      \[{{\tau }_{2}}=\frac{1}{2}{{\tau }_{1}}\] \[\therefore \] \[MB\,\,\sin \,\theta =\frac{1}{2}MB\] \[\therefore \] \[\sin \,\theta =\frac{1}{2}\] Angle of rotation is \[={{90}^{o}}-{{30}^{o}}={{60}^{o}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner