A) is ahead in phase by n
B) lags in phase by n
C) is ahead in phase by ?
D) lags in phase by ?
Correct Answer: D
Solution :
In a purely inductive circuit, current is \[i={{i}_{0}}\,\,\sin \,\left( \omega t-\frac{\pi }{2} \right)\]
Which shows that the current lags behind the emf by a phase angle of \[\frac{\pi }{2}\] or \[{{90}^{o}}\] or the emf leads the current by a phase angle of \[\frac{\pi }{2}\] or \[{{90}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
