A) \[0.1\text{ }V\]
B) \[0.5\,\,V\]
C) \[1\,\,V\]
D) \[-5\,\,V\]
Correct Answer: D
Solution :
The magnetic flux through area A placed in magnetic field B is \[\phi =BA\,\,\cos \,\theta \] Given, \[\theta ={{0}^{o}},\,\,\,\,B=1\,T/s,\] \[A={{(10)}^{2}}c{{m}^{2}}={{10}^{-2}}\,{{m}^{2}}\] \[\therefore \] \[\phi =1\times {{10}^{-2}}\] By Faraday's law, induced emf is \[e=-N\frac{\Delta \phi }{\Delta t}\] \[=-500\times {{10}^{-2}}=-5\,V\]
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