A) \[200\text{ }W\]
B) \[100\sqrt{3\,}W\]
C) \[50\,W\]
D) zero
Correct Answer: A
Solution :
Power (P) is given as \[P=F.v=Fv\,\,\cos \,\theta \] where F is force, v the velocity and \[\theta \] the angle between F and v. \[P=mgv\,\,\cos \,\theta \] Given, \[m=2kg,\text{ }v=20\text{ }m/s,\text{ }\theta ={{60}^{o}}\] \[\therefore \] \[P=2\times 20\times 10\times \cos \,{{60}^{o}}\] \[P=2\times 20\times 10\times \frac{1}{2}\] \[\Rightarrow \] \[P=200W\]You need to login to perform this action.
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