A) \[x=1\]only
B) \[x=1\] and \[x=-1\]only
C) \[x=1,\,x=-1,\,x=-3\]only
D) \[x=1,\,x=-1,\,x=-3\] and other values of x
Correct Answer: C
Solution :
Given, \[f(x)=\frac{2{{x}^{2}}+7}{{{x}^{3}}+3{{x}^{2}}-x-3}\] \[=\frac{2{{x}^{2}}+7}{({{x}^{2}}-1)(x+3)}\] At \[x=1,\,\,f(x)=\infty \] \[x=-1,\,f(x)=\infty \] \[x=-3,\,f(x)=\infty \] \[\therefore \] At \[x=1,\,\,\,x=-1\] and \[x=-3\] function is discontinuous
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