A) \[3/2\]
B) \[7/2\]
C) \[2/5\]
D) \[0\]
Correct Answer: B
Solution :
Distance between the plane \[4x+2y+4z-16=0\] and \[4x+2y+4z+5=0\] is \[d=\frac{|5+16|}{\sqrt{16+4+16}}=\frac{|21|}{\sqrt{36}}=\frac{21}{6}=\frac{7}{2}\]You need to login to perform this action.
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