A) \[\frac{a}{b}\]
B) \[-\frac{a}{b}\]
C) \[\frac{a}{2b}\]
D) \[-\frac{1}{ab}\]
Correct Answer: B
Solution :
When temperature of the hot junction of a thermocouple rises, the thermo emf increases and becomes maximum at a particular temperature. This temperature is called neutral temperature. Given, \[e=at+\frac{1}{2}b{{t}^{2}}\] Differentiating with respect to t, we get \[\frac{de}{dt}=a+bt\] For maximum value of e, \[\frac{de}{dt}=0\] \[\therefore \] \[a+bt=0\,\,\,\Rightarrow \,\,\,t=-\frac{a}{b}\]
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