A) \[\frac{50}{11}\]
B) \[\frac{51}{11}\]
C) \[\frac{11}{50}\]
D) None of these
Correct Answer: C
Solution :
Required probability \[=\frac{\frac{1}{4}\times \frac{^{12}{{C}_{2}}}{^{52}{{C}_{2}}}}{\frac{\frac{1}{4}{{\times }^{12}}{{C}_{2}}}{^{52}{{C}_{2}}}+\frac{\frac{3}{4}{{\times }^{13}}{{C}_{2}}}{^{52}{{C}_{2}}}}\] \[=\frac{\frac{66}{4}}{\frac{66}{4}+\frac{234}{4}}=\frac{66}{300}=\frac{11}{50}\]
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