A) \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{1}}\]
B) \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{1}}\]
C) \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{1}}3{{p}^{2}}\]
D) \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}\]
Correct Answer: A
Solution :
\[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{1}}\]configuration represents the Na, because the atomic number of Na is 11. The first ionisation energy is less than second ionisation energy because\[\text{I}{{\text{E}}_{\text{2}}}\]involves the removal of an electron from the stable configuration (\[\text{ie,}\]\[\text{1}{{\text{s}}^{2}},2{{s}^{2}}2{{p}^{6}}\])
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