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J & K CET Engineering J and K - CET Engineering Solved Paper-2004

  • question_answer
    The hydrogen electrode is dipped in a solution of \[pH=3\]at \[25{{\,}^{o}}C.\] The potential of the cell would be (the value of.2.303 RT/F is 0.059 V)

    A) \[~0.177\,V\]      

    B) \[~0.087\,V\]

    C) \[~-0.177\,V\]     

    D) \[0.059\,V\]

    Correct Answer: C

    Solution :

     \[{{H}^{+}}+{{e}^{-}}\xrightarrow{{}}\frac{1}{2}{{H}_{2}}\] \[E={{E}^{o}}-\frac{0.059}{n}\log \frac{1}{[{{H}^{+}}]}\] \[=0-\frac{0.059}{1}pH\] \[E=-0.059\times 3=-0.177\,V\]


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