A) \[[F{{L}^{-1}}{{T}^{2}}]\]
B) \[[F{{L}^{-1}}{{T}^{-2}}]\]
C) \[[F{{L}^{-1}}{{T}^{-1}}]\]
D) \[[F{{L}^{2}}{{T}^{2}}]\]
Correct Answer: A
Solution :
From Newton's second law Force (F) = Mass (M) \[\times \] acceleration \[\therefore \] Dimensions of \[[F]=[ML{{T}^{-2}}]\] \[\Rightarrow \] \[[M]=[F{{L}^{-1}}{{T}^{2}}]\]
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