A) \[\frac{a}{b}\]
B) \[-\frac{a}{b}\]
C) \[\frac{a}{2b}\]
D) \[-\frac{a}{2b}\]
Correct Answer: D
Solution :
In a thermocouple as temperature of the hot junction rises, the thermo emf rises and becomes maximum at a particular temperature. This temperature is called neutral temperature. Given, \[e=at+b{{t}^{2}}\] At neutral temperature \[\frac{de}{dt}=0\] \[\therefore \] \[\frac{de}{dt}=a+2bt=0\] \[\Rightarrow \] \[t=-\frac{a}{2b}\]
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