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J & K CET Engineering J and K - CET Engineering Solved Paper-2003

  • question_answer
    Eccentricity of the curve \[{{x}^{2}}-{{y}^{2}}={{a}^{2}}\]is equal to

    A)  \[2\]             

    B)  \[\sqrt{2}\]

    C)  \[4\]            

    D)  None of these

    Correct Answer: B

    Solution :

    Given equation of curve can be rewritten as \[\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{a}^{2}}}=1\] \[\therefore \] \[e=\sqrt{1+\frac{{{b}^{2}}}{{{a}^{2}}}}=\sqrt{1+\frac{{{a}^{2}}}{{{a}^{2}}}}\] \[\Rightarrow \] \[e=\sqrt{2}\]


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