2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2003

  • question_answer
    The third term of a GP is 4. The product of its first five terms is

    A)  \[{{4}^{5/2}}\]         

    B)  \[{{4}^{5}}\]

    C)  \[{{4}^{3}}\]

    D)  None of these

    Correct Answer: B

    Solution :

    Let a and r be the first term and common ratio of a GP.         \[\therefore \] \[{{T}_{3}}=4\]                 \[\Rightarrow \] \[a{{r}^{2}}=4\] ??(i) Now,   \[a.\,a{{r}^{1}}.\,\,a{{r}^{2}}\,.\,a{{r}^{3}}\,.a{{r}^{4}}\] \[={{(a{{r}^{2}})}^{5}}={{(4)}^{5}}\] [from Eq. (i)]


You need to login to perform this action.
You will be redirected in 3 sec spinner