J & K CET Engineering J and K - CET Engineering Solved Paper-2003

  • question_answer
    Half-life of a sample is 160 days. After 800 days, 1 g of the sample shall be reduced to

    A)  \[\frac{1}{2}g\]

    B) \[\frac{1}{5}g\]

    C)  \[\frac{1}{4}g\]

    D)  \[\frac{1}{32}g\]

    Correct Answer: D

    Solution :

     \[T=800\,\]days \[{{t}_{1/2}}=160\,\] \[n=\frac{T}{{{t}_{1/2}}}=\frac{800}{160}=5\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}=1{{\left( \frac{1}{2} \right)}^{5}}\] \[N=\frac{1}{32}g\]


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