J & K CET Engineering J and K - CET Engineering Solved Paper-2003

  • question_answer
    The electrons identified by quantum numbers:
    (I) \[n=4,l=1\]
    (II) \[n=4,l=0\]
    (III) \[n=3,l=2\]
    (IV) \[n=2,l=1\]
    can be placed in order of increasing energy from the lowest to highest as

    A)  \[(IV)<(II)<(III)<(I)\]

    B) \[(II)<(IV)<(I)<(III)\]

    C)  \[(I)<(III)<(II)<(IV)\]

    D)  \[(III)<(I)<(IV)<(II)\]

    Correct Answer: A

    Solution :

    (I) For\[n=4,\,l=1;4p\]
    (II) For \[n=4,l=0;4s\]
    (III) For \[n=3,l=2;3d\]
    (IV) For \[n=2,\,l=1;2p\]
    The order of increasing energy is as: \[2p<4s<3d<4p\] \[ie,\]\[(IV)<(II)<(III)<(I)\]


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