A) \[Mg\left( 1-\frac{{{d}_{2}}}{{{d}_{1}}} \right)\]
B) \[Mg\frac{{{d}_{1}}}{{{d}_{2}}}\]
C) \[Mg({{d}_{1}}-{{d}_{2}})\]
D) \[Mg{{d}_{1}}{{d}_{2}}\]
Correct Answer: A
Solution :
At terminal velocity is the speed at which the gravitational force pulling it downwards is equal and opposite to the atmospheric drag, at this speed the object ceases to accelerate down- wards and falls at constant speed. \[\therefore \] Viscous force upwards = Apparent weight in liquid \[\therefore \] Viscous force \[=Mg-\frac{Mg{{d}_{2}}}{{{d}_{1}}}\] Viscous force \[=Mg\left( 1-\frac{{{d}_{2}}}{{{d}_{1}}} \right)\]
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