A) Stephens reduction
B) Cannizaros reaction
C) Clemmensen reduction
D) Rosenmunds reduction
Correct Answer: A
Solution :
In the Stephens reduction, alkyl cyanide is reduced to aldehyde by \[SnC{{l}_{2}}/HCl\]. \[RC\equiv N+2H\xrightarrow{SnC{{l}_{2}}/HCl}\underset{\begin{smallmatrix} \text{aldimine} \\ \text{hydrochloride} \end{smallmatrix}}{\mathop{RCH=NH.HCl}}\,\] \[\xrightarrow{{{H}_{2}}O}RCHO+N{{H}_{4}}Cl\]
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