2. Solved Papers
  3. Haryana PMT

Haryana PMT Haryana PMT Solved Paper-2011

  • question_answer
    The ionization energy of a hydrogen atom is       13.6 eV. Following Bohrs theory, the energy corresponding to a transition between 3rd and          4th orbit is

    A)                  3.40 eV                               

    B)  1.51 eV

    C)                  0.85 eV                               

    D)  0.66 eV

    Correct Answer: D

    Solution :

                    \[E={{E}_{4}}-{{E}_{3}}\]                 \[=-\frac{13.6}{{{4}^{2}}}-\left( \frac{13.6}{{{3}^{2}}} \right)\]                 \[=-0.85\times 1.51\]                 \[=0.66\,eV\]


You need to login to perform this action.
You will be redirected in 3 sec spinner