A) 4R
B) \[\frac{R}{4}\]
C) \[\frac{R}{16}\]
D) 16R
Correct Answer: B
Solution :
Resistance, \[\text{R=}\,\rho \frac{\text{l}}{\text{A}}\] \[\therefore \] \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\times \frac{{{A}_{2}}}{{{A}_{1}}}\] \[\frac{{{R}_{{}}}}{{{R}_{2}}}=\frac{{{l}_{{}}}}{{{l}_{{}}}}\times \frac{{{4}_{a}}}{a}\] \[{{\text{R}}_{\text{2}}}\text{ }\!\!\times\!\!\text{ }\frac{\text{R}}{\text{4}}\]
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