Haryana PMT Haryana PMT Solved Paper-2010

  • question_answer
    The length of one turn of the helix in B-form DNA is approximately

    A)  0.34 nm              

    B)  20 nm

    C)  2nm                                     

    D)  3.4 nm

    Correct Answer: D

    Solution :

                    B-form of DNA shows right-handed coiling which contains 10 base pairs in each turn. On complete turn, DNA occupies 34 A distance. So in nm, it will 3.4 nm because  or.                 \[\begin{align}   & 1nm={{10}^{-9}}m \\  & 1\overset{\text{o}}{\mathop{\text{A}}}\,={{10}^{10}}m \\  & 34\overset{0}{\mathop{\text{A}}}\,=34x{{10}^{10}}m \\  & =3.4nm \\ \end{align}\] So,


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