A) \[{{H}_{2}}\] with Pd catalyst
B) glycerol with \[KOH\]
C) \[LiAl{{H}_{4}}\] with water
D) \[Zn-Hg\]with \[HCl\]
Correct Answer: D
Solution :
Reduction of aldehydes and ketones to their corresponding hydrocarbons in the presence of \[Zn-Hg\] with cone \[HCl\] is known as Clemmensens reduction, eg,\[\underset{acetaldehyde}{\mathop{C{{H}_{3}}CHO}}\,+4[H]\xrightarrow[conc.\,HCl]{Zn/Hg}\underset{etthane}{\mathop{C{{H}_{3}}C{{H}_{3}}}}\,+{{H}_{2}}O\]
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