A) \[1.459\]
B) \[0.459\]
C) \[4.159\]
D) None of these
Correct Answer: B
Solution :
\[\because \] Mole fraction of a component \[=\frac{no.\text{ }of\text{ }moles\text{ }of\text{ }the\text{ }component}{total\text{ }no.\text{ }of\text{ }moles\text{ }of\text{ }all\text{ }components}\]Given, mass of benzene \[=30\text{ }g\] So, moles of benzene \[=\frac{30}{78}\] \[\because \] Mol. mass of \[C{{ & }_{6}}{{H}_{6}}=78)\] \[=0.385\] Mass of \[CC{{l}_{4}}=70g\] Moles of \[CC{{l}_{4}}=\frac{70}{154}\] (\[\because \] Mol. mass of \[CC{{l}_{4}}=15.4\]) \[=0.454\] \[\therefore \] Mole fraction of benzene \[{{\chi }_{{{C}_{6}}{{H}_{6}}}}=\frac{0.385}{0.385+0.454}\] \[=0.459\]
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