A) \[HClO<HCl{{O}_{2}}<HCl{{O}_{3}}<HCl{{O}_{4}}\]
B) \[HCl{{O}_{4}}<HCl{{O}_{3}}<HCl{{O}_{2}}<HClO\]
C) \[HClO<HCl{{O}_{4}}<HCl{{O}_{3}}<HCl{{O}_{2}}\]
D) \[HCl{{O}_{4}}<HCl{{O}_{2}}<HCl{{O}_{3}}<HClO\]
Correct Answer: A
Solution :
As the oxidation number of Cl-atbm increases from \[HClO\] to \[HCl{{O}_{4}}\](ie, \[+1\] to \[+7\]), the possibility of getting H atom as \[{{H}^{+}}\] ion by the rupture of \[O-H\] bond increases. Hence, the correct order of acidity is\[\overset{+1}{\mathop{HClO}}\,<\overset{+3}{\mathop{HCl{{O}_{2}}}}\,<\overset{+5}{\mathop{HCl{{O}_{3}}}}\,<\overset{+7}{\mathop{HCl{{O}_{4}}}}\,\]
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