A) as large as possible
B) any number
C) 2
D) 1
Correct Answer: D
Solution :
Maximum torque, \[{{\tau }_{\max }}=MB\] or \[{{\tau }_{\max }}=ni\pi {{r}^{2}}B\] Let number of turns in length \[l\] is n so \[l=n(2\pi r)\] or \[r=\frac{l}{2\pi n}\] \[\Rightarrow \] \[{{\tau }_{\max }}=\frac{ni\pi B{{l}^{2}}}{4{{\pi }^{2}}{{n}^{2}}}=\frac{{{l}^{2}}iB}{4\pi {{n}_{\min }}}\] \[\Rightarrow \] \[{{\tau }_{\max }}\propto \frac{1}{{{n}_{\min }}}\] \[\Rightarrow \] \[{{n}_{\max }}=1\]
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