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Haryana PMT Haryana PMT Solved Paper-2010

  • question_answer
    A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M. If the block rises to a S haight the initial velocity of the block will be

    A) \[\sqrt{2gh}\]                                   

    B) \[\frac{m+m}{m}\sqrt{2gh}\]

    C)  \[\frac{m}{M+m}2gh\]                

    D)  \[\frac{M+m}{M}\sqrt{2gh}\]

    Correct Answer: A

    Solution :

                    Initial KE of block when bullet strikes to it \[=\frac{1}{2}(m+M){{v}^{2}}\] Due to this KE of block will rise to a height h.    Its potential energy \[=(m+M)gh\] By the law of conservation of energy \[\frac{1}{2}(m+M){{v}^{2}}=(m+M)gh\] \[\therefore \]  \[v=\sqrt{2gh}\]


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