A) \[{{H}_{3}}P{{O}_{3}}\]
B) \[HP{{O}_{3}}\]
C) \[{{H}_{3}}P{{O}_{2}}\]
D) \[{{H}_{3}}P{{O}_{4}}\]
Correct Answer: D
Solution :
\[PC{{l}_{5}}\], on hydrolysis, with insufficient quantity of water, gives \[POC{{l}_{3}}\] while with excess of water gives phosphoric acid, \[({{H}_{3}}P{{O}_{4}})\]. \[PC{{l}_{5}}+4{{H}_{2}}O\xrightarrow{Excess\,of\,water}{{H}_{3}}P{{O}_{4}}+5HCl\]
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