Haryana PMT Haryana PMT Solved Paper-2009

  • question_answer
    Standard free energy change for an equilibrium is zero, the value of \[{{K}_{p}}\] is

    A)  zero                                     

    B)  \[1\]

    C)  \[2\]                                    

    D)  \[100\]

    Correct Answer: B

    Solution :

                    Standard free energy change, \[\Delta {{G}^{o}}=-2.303RT\,\log \,{{K}_{p}}\] If           \[\Delta {{G}^{o}}=0\] \[\Rightarrow \]               \[0=-2.303RT\,\log {{K}_{p}}\]                 \[\log {{K}_{p}}=0\] \[\therefore \]  \[{{K}_{p}}=1\]


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