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Haryana PMT Haryana PMT Solved Paper-2009

  • question_answer
    45.          A current passing through a coil of self-inductance of 2 mH changes at the rate of 20 mA s-1. The emf induced in the coil is

    A)  \[\text{10 }\!\!\mu\!\!\text{ V}\]                          

    B)  \[\text{40 }\!\!\mu\!\!\text{ V}\]

    C)  \[\text{10mV}\]                             

    D)  \[\text{10mV}\]

    Correct Answer: B

    Solution :

                    By Faradays second law, induced emf \[e=-\frac{Nd\phi }{dt}\] which gives \[e=-L\frac{dI}{dt}\] \[\therefore \]  \[|e|=2\times {{10}^{-3}}\times 20\times {{10}^{-3}}V=40\mu V\]


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