A) ethanamide
B) methanamine
C) ethanamine
D) formic acid
Correct Answer: B
Solution :
\[\underset{(\text{Hofmann }\!\!\!\!\text{ s bromamide reaction)}}{\mathop{C{{H}_{3}}CON{{H}_{2}}\xrightarrow{NaOH/O{{H}^{-}}}C{{H}_{3}}N{{H}_{2}}}}\,\]
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