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Haryana PMT Haryana PMT Solved Paper-2008

  • question_answer
    The \[\Delta H\] value of the reaction,\[{{H}_{2}}+C{{l}_{2}}2HCl\] is \[-44.2kcal\] If \[{{E}_{1}}\] is the activation energy of the forward reaction, then for the above reaction activation energy of reverse reaction \[{{E}_{2}}\] is

    A)  \[{{E}_{1}}>{{E}_{2}}\]                     

    B)  \[{{E}_{1}}<{{E}_{2}}\]

    C)  \[{{E}_{1}}={{E}_{2}}\]

    D)  \[\Delta H\] is not related to \[{{E}_{1}}\] and \[{{E}_{2}}\]

    Correct Answer: B

    Solution :

                    \[{{H}_{2}}+C{{l}_{2}}2HCl,\]    \[\Delta H=-44.2kcal\] Above reaction is exothermic, so the activation energy of forward reaction \[({{E}_{1}})\] is less than activation energy of reverse reaction \[({{E}_{2}})\], ie, \[{{E}_{1}}<{{E}_{2}}\]


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