A) \[2\]
B) \[16\]
C) \[32\]
D) \[30\]
Correct Answer: D
Solution :
\[n=1\], no. of orbital \[=1(s)\] \[n=2\], no. of orbitals \[=4\] (5 and p) \[n=3\], no. of orbitals \[=9\](s p, d) \[\frac{\text{n = 4 }no.\text{ }of\text{ }orbitals\,\,(e\text{ }p,\text{ }d,\text{ }f)}{Total\text{ }no.\text{ }of\text{ }orbitals=30}\]
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