A) \[{{C}_{2}}{{H}_{2}}\]
B) \[{{C}_{2}}{{H}_{4}}\]
C) \[{{C}_{6}}{{H}_{6}}\]
D) \[C{{H}_{2}}=CHCH=C{{H}_{2}}\]
Correct Answer: B
Solution :
\[\xrightarrow[-{{H}_{2}}{{O}_{2}}]{{{H}_{3}}{{O}^{+}}}2HCHO\]
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