Haryana PMT Haryana PMT Solved Paper-2006

  • question_answer
    Ethyl alcohol is heated with cone. \[{{H}_{2}}S{{O}_{4}}\]. The product formed is:

    A)  \[C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O{{C}_{2}}{{H}_{5}}\]

    B)  \[{{C}_{2}}{{H}_{6}}\]

    C)  \[{{C}_{2}}{{H}_{4}}\]

    D)  \[{{C}_{2}}{{H}_{2}}\]

    Correct Answer: C

    Solution :

                    Ethyl .alcohol on dehydration with cone. \[{{H}_{2}}S{{O}_{4}}\] at\[{{170}^{o}}C\], gives ethylene. \[C{{H}_{3}}C{{H}_{2}}OH\xrightarrow[conc.\,{{H}_{2}}S{{O}_{4}}]{{{170}^{o}}C}\underset{Ethylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}O}}\,\]


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