A) \[1.5\times {{10}^{-5}}Nm\]
B) \[1.5\times {{10}^{-3}}Nm\]
C) \[1.5\times {{10}^{-2}}Nm\]
D) \[1.5\times {{10}^{-6}}Nm\]
Correct Answer: A
Solution :
\[C=MB\,\,\sin \theta \] \[=(m\times 2l)\times 2\times {{10}^{-5}}\,\sin {{30}^{o}}\] \[=15\times 10\times {{10}^{-2}}\times 2\times {{10}^{-5}}\times \frac{1}{2}\] \[=1.5\times {{10}^{-5}}Nm\]
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