A) \[212.3\text{ }kJ\]
B) \[175.4\text{ }kJ\]
C) \[106.15\text{ }kJ\]
D) \[350.8\text{ }kJ\]
Correct Answer: B
Solution :
Electrical work \[=nFE_{cell}^{o}\] \[=2\times 96500\times 1.1=212300Joules\] \[=212.3kJ\]
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