Haryana PMT Haryana PMT Solved Paper-2005

  • question_answer
    An L.P.G; cylinder, containing \[15kg\] butane at \[{{27}^{o}}C\] and 10 atmospheric pressure, is leaking. After one day its pressure decreased to 8 atmosphere. The quantity of gas leaked is:

    A)  \[1kg\]                                

    B)  \[2kg\]

    C)  \[3kg\]                                

    D)  \[4kg\]

    Correct Answer: C

    Solution :

                    According to question, temperature and volume are constant, hence from ideal gas equation, we have \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{n}_{1}}}{{{n}_{2}}}\]                 or            \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{\omega }_{1}}}{{{\omega }_{2}}}\]                 \[\therefore \]  \[\frac{10}{8}=\frac{15}{{{\omega }_{2}}}\]                                 \[{{\omega }_{2}}=12kg\] Hence, gas leaked \[=15-12=3kg\]


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