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Haryana PMT Haryana PMT Solved Paper-2005

  • question_answer
    In the reaction\[A(s)+B(g)+heat\]\[2C(s)+2D(g)\]at equilibrium, pressure of B is doubled to re-establish the equilibrium. The factor by which concentration of D is changed, is:

    A)  \[\sqrt{2}\]                                       

    B)  \[2\]

    C)  \[3\]                                    

    D)  \[2\sqrt{2}\]

    Correct Answer: A

    Solution :

                    For reaction, \[{{K}_{p}}=\frac{{{[D]}^{2}}}{[B]}\] Hence, for this reaction,                 \[\frac{{{[{{D}_{1}}]}^{2}}}{[{{B}_{1}}]}=\frac{{{[{{D}_{2}}]}^{2}}}{[2{{B}_{1}}]}\] or            \[[{{D}_{2}}]=\sqrt{2}[{{D}_{1}}]\]


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