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Haryana PMT Haryana PMT Solved Paper-2005

  • question_answer
    If a, b, c and d are mass, length, time and current respectively, then \[{{b}^{2}}a/{{c}^{3}}d\] has the dimensions of :

    A)  capacitance                      

    B)  electric field

    C)  permittivity                      

    D)  electric potential

    Correct Answer: A

    Solution :

                    As given \[[a]=[M],\,[b]=[L],\,[c]=[T]\]and \[[d]=[A]\] Therefore, \[\frac{a{{b}^{2}}}{{{c}^{2}}d}=\frac{[M][{{L}^{2}}]}{[{{T}^{3}}][A]}=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[AT]}\]\[=\frac{work}{\text{charge}}=\] electric potential


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